液相色谱

今天碰到一个外文标准，看后很头疼，希望请园里的高手给翻译下。
In the chromatogram obtained with solution(1), the area of any peak due to the tenofovir monoester is not greater than twice the area of the principal peak obtained with solution(2)(1.0%). In the chromatogram obtained with solution(1), the area of not more than one peak, other than the principal peak, is greater than the area of the principal peak obtained with solution(2)(0.5%) and the areas of not more than two such peaks are greater than 0.4 times the areas of the principal peak obtained with solution(2)(0.2%). The sum of the areas of all peaks, other than the principal peak, is not greater than 5 times the area of the principal peak obtained in the chromatogram with solution(3) and any peak with an area less than 0.5 times the area of the principal peak in the chromatogram obtained with solution(2)(0.05%). Disregard any peak corresponding to the peak obtained in the chromatogram with solution(3) and any peak with an area less than 0.5 times the area of the principal peak in the chromatogram obtained with solution(2)( 0.05%).

在色谱获得同解(1)，罚球区在所有的高峰当中由于泰诺福韦单酯不是大于两次校长的罚球区山峰获得同解(2)(1。0%)。在色谱获得同解(1)，不的罚球区不止一个高峰，除了校长高峰，大于校长的罚球区高峰获得同解(2)(0。5%)，不超过的地区二如此高峰大于0。4次地区的校长高峰鄂毕河.总和的地区的所有高峰，除了校长山峰，不是大于5时间校长的罚球区高峰获得在色谱同解(3)，任何高峰同一个地区少于0。5时间校长的罚球区高峰在色谱获得同解(2)(0。05%).漠视任何高峰相应的高峰获得在色谱同解(3)，任何高峰同一个地区少于0。5时间校长的罚球区高峰在色谱获得同解(2)(0。05%)。

这是关于“有关物质检查”的一段，solution(1)是样品溶液，solution(2)(3)是不同浓度的对照品溶液，直接翻译是这样的：

在溶液（1）获取的色谱图中，由替诺福韦单酯产生的有关峰的面积不能大于溶液（2）获得的主峰面积的2倍（这样的峰含量相当于小于1.0%）。
在溶液（1）获取的色谱图中，除主峰外，最多只能有一个峰面积大于溶液（2）获得的主峰面积（这样的峰含量相当于大于0.5%）并且最多只能有2个峰的面积大于溶液（2）所获主峰面积的0.4倍（这样的峰含量相当于大于0.2%）。
除主峰外，所有峰的面积之和，不能大于溶液（3）所获主峰面积的5倍并且各峰的面积应低于0.5倍溶液（2）的主峰面积（0.05%）。
不考虑所有与溶液（3）所获峰一致的峰和低于0.5倍溶液（2）的主峰面积的峰（0.05%）。

最后两句话的意思和那两个“0.05%”我也没搞明白，期待高手予以解释。

[ 本帖最后由 猴子 于 2010-10-28 17:58 编辑 ]

下个有道词典，就可以查到不认识单词的意思，然后再根据所掌握的专业知识和英语知识就可以翻译了，像这种还是自己亲手翻译才可以有印象，而且能掌握不认识的单词。

在含有溶液1的色谱图中，任何泰洛福韦单酯峰面积不得超过溶液2（1.0%）主峰面积的两倍。

做个提示，以后 的请自主翻译。

这个确实看着头晕，翻译了一下，有问题LZ自己再改改吧
译文如下：

溶液(1)获得的色谱图中，对应于泰诺福韦一元酯的任何峰面积不大于1.0％（不知道是质量分数还是体积分数，后同）的溶液(2)所获得的主峰面积的两倍。溶液(1)溶液获得的色谱图中，除主峰外的任意一个峰面积大于0.5％的溶液(2)所获得的主峰面积，并且任意两个峰面积大于0.2％的溶液(2)所获得的主峰面积的0.4倍。溶液(1)除主峰外的所有峰面积之和不大于溶液(3)所获得主峰面积的5倍，并且不大于0.05％的溶液(2)所获得峰面积小于0.5倍所获主峰面积的任一峰面积。忽略溶液(3)获得的所有色谱峰和0.05％溶液(2)中峰面积小于0.5倍主峰面积的任一峰。

In the chromatogram obtained with solution(1), the area of any peak due to the tenofovir monoester is not greater than twice the area of the principal peak obtained with solution(2)(1.0%). In the chromatogram obtained with solution(1), the area of not more than one peak, other than the principal peak, is greater than the area of the principal peak obtained with solution(2)(0.5%) and the areas of not more than two such peaks are greater than 0.4 times the areas of the principal peak obtained with solution(2)(0.2%). The sum of the areas of all peaks, other than the principal peak, is not greater than 5 times the area of the principal peak obtained in the chromatogram with solution(3) and any peak with an area less than 0.5 times the area of the principal peak in the chromatogram obtained with solution(2)(0.05%). Disregard any peak corresponding to the peak obtained in the chromatogram with solution(3) and any peak with an area less than 0.5 times the area of the principal peak in the chromatogram obtained with solution(2)( 0.05%).



在溶液1所获得的色谱图中，任何泰洛福韦单脂的峰面积不得超过溶液2主峰面积的2倍(1.0%)。在溶液1所获得的色谱图中，除主峰外，大于溶液2主峰面积的峰(0.5%)不得超过1个，并且大于溶液2主峰面积0.4倍的峰(0.2%)不得超过2个。除主峰外所有峰面积的总和不得超过溶液3主峰面积的5倍。忽略溶液3色谱图中相应的峰以及任何低于溶液2主峰面积0.5倍的峰。



感觉红色的部分是不是粘贴错误？不太好理解呀