小中大瞬态吸收光谱分析
大家好,最近看到一篇文献里的瞬态吸收光谱,刚接触瞬态吸收光谱,理解不了,希望高手指导一下,谢谢!
文献图附在下面,文章解析部分:The transient spectra of [Ru(bpy)3]2+in the presence of
[S2O8]2− after 400 nm excitation is shown in Figure 8a. The bleach band at 450 nm is due to the photoinduced depopulation of ground state [Ru(bpy)3]2+。The absorptionfeature above ∼500 nm results from the new species: [Ru(bpy)3]2+* and [Ru(bpy)3]3+. The spectral evolution in this area is due to the conversion from [Ru(bpy)3]2+* to [Ru(bpy)3]3+。Because the radical reaction further depopulates the ground state of [Ru(bpy)3]2+, it results in the further growth of the bleach band in Figure 8a.
我的问题:
1、“bleach band ”的物理意义是什么?是谁的峰?与[Ru(bpy)3]2+的关系是什么?
2、为什么激发波长为400 nm,而检测的“bleach band ”在450 nm?
3、500 nm 左右的吸收峰是指大于零基准线的部分吗?